Answer:
- The smallest area the field could be is 6,400 m²
- The largest area the field could be is 8,250 m²
Step-by-step explanation:
Given;
smallest possible length of the international soccer field, L₀ = 100 m
smallest possible breadth of the international soccer field, B₀ = 64 m
Largest possible length of the international soccer field, L₁ = 110 m
Largest possible breadth of the international soccer field, B₁ = 75 m
Area of a rectangle is given by;
A = L x B
The smallest area the field could be is calculated as;
A₀ = L₀ x B₀
A₀ = 100 m x 64 m
A₀ = 6,400 m²
The largest area the field could be is calculated as;
A₁ = L₁ x B₁
A₁ = 110 m x 75 m
A₁ = 8,250 m²
Answer:
The step 3 is incorrect in the conversion, is not necessary
Step-by-step explanation:
we have
The speed is 
we know that
1 mm=0.1 cm
1 min=1/60 h
so
step 1
Multiply 76 by 0.1
The step 1 is correct
step 2
Multiply the result obtained in step 1 by 60.
The step 2 is correct
step 3
Multiply the result obtained in step 2 by 60
<u><em>This step is not correct</em></u>
therefore
The step 3 is incorrect in the conversion, is not necessary
I think that is 105.x = dbc 1/2 but I am not Shure that is what they are telling me
Sqrt(5/3)
and
sqrt(0/6)
many square roots are irrational numbers as long as they are not a perfect square
|-3| becomes positive 3
0.6 can be converted into a fraction 6/10
Answer:
You would put an open dot on both ends from -8 to 4 or just a distance of 12
Step-by-step explanation:
