Can someone write an equation for me ?

What is the slope of the line that passing through (-2, 4) and the origin.

S_A_V [24]

Answer:

slope= -2

Step-by-step explanation:

using $\frac{y2-y1}{x2-x1}$ you plug in the values of (-2,4) and (0,0)

= $\frac{0-4}{0-(-2)}$

= $\frac{-4}{2}$

= -2

8 0

3 years ago

Read 2 more answers

Frankie runs every third day Ryan runs every sixth day.In the next 100 days how many times will Frankie and Ryan run on the same

Papessa [141]

Answer:

16 times

Step-by-step explanation:

To find how many times Frankie and Ryan run on the same day in the next 100 days, find the common multiples of 3 days and 6 days to 100 days

Frankie (every third day) = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99.

Ryan (every sixth day) = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96.

Common multiples of 3 days and 6 days = 12, 18, 24, 30, 36, 42, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96.

Frankie and Ryan will run on the same day 16 times in the next 100 days

6 0

3 years ago

In parallelogram FGHJ if m∡ GHJ=55˚ find m∡FGH

hodyreva [135]

Answer:

∠ FGH = 125°

Step-by-step explanation:

The consecutive angles in a parallelogram are supplementary, then

∠ FGH + ∠ GHJ = 180° , that is

∠ FGH + 55° = 180° ( subtract 55° from both sides )

∠ FGH = 125°

4 0

2 years ago

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What a bar or a line is placed over repeating digits the number is written by using blank

Pavlova-9 [17]

The bar or line the is placed over repeating digits in a decimal in called a vinculum

7 0

3 years ago

A warehouse distributor of carpet faces a normally distributed demand for its carpet. The average demand for carpet from the sto

Snezhnost [94]

Answer with Step-by-step explanation:

Since the demand is normally distributed the required probability can be found from the area under the normal distribution curve as

Part a)

Given mean = 4500 yards per month

Standard deviation = 900 yards

Thus area under the curve corresponding to 6000 yards is found from the standard variate factor Z as

$Z=\frac{X-\bar{X}}{\sigma }\\\\Z=\frac{6000-4500}{900}=1.67$

Area for Z = 1.67 = 95.22%

Thus the probability that the demand will be met is 0.9522 hence the probability that the demand will not be met is $P(E)=1-0.9522=0.0478$

Part b)

The reuired answer is area between 5000 and 7000 yards in the normal distribution curve thus we have

$Z_1=\frac{5000-4500}{900}=0.56$ .

$Z_2=\frac{7000-4500}{900}=2.78$

The area between these 2 values is 49.73% hence the reuired probability is 0.4973.

Part c)

For 97% satisfaction of demand the Z factor corresponding to 97% of area is found to be 1.88

thus we can write

$1.88=\frac{X-4500}{900}\\\\X=4500+1.88\times 1.88=6193$

4 0

3 years ago