Question

Calculate the calories lost when 85 g of water cools from 45 degrees Celsius to 23 degrees Celsius

Answer 1

The amount of heat lost by the water is 1870 calories

Step-by-step explanation:

The amount of heat released by a substance is given by the equation

$Q=mC\Delta T$

where

Q is the amount of heat lost

m is the mass of the substance

C is the specific heat capacity of the substance

$\Delta T$ is its change in temperature

In this problem, we have:

m = 85 g is the mass of water

$C=1 cal /g^{\circ}C$ is the specific heat capacity of water

$\Delta T = 23-45=-22^{\circ}C$ is the change in temperature of the water

Substituting, we find

$Q=(85)(1)(-22)=-1870 cal$

Learn more about heat:

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