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Katena32 [7]
3 years ago
5

Is 4,320 grams greater than 4,32 kilograms ?

Mathematics
2 answers:
tatuchka [14]3 years ago
5 0

No, small ....... otherwise your question is wrong......

=>4320/1000=4.32

////////////??????????

=>(,)-------(.).......4(.)32/4(,)32

Which is this?

ozzi3 years ago
3 0

Answer: No, it is equal.

Step-by-step explanation:

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F
lina2011 [118]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
Read 2 more answers
Why are expressions 3(y-2)+2(y-2) and 5(y-2) equivalent
AlladinOne [14]
3(y-2) + 2(y-2) = 5(y-2)

Both terms have the base (y-2), so they can be added together.
3 + 2 = 5
6 0
3 years ago
Select the expressions that are equivalent to18m - 12
bezimeni [28]
A,C,D are equivalent to 18m -12 as solving each of them will give you 18m-12.

8 0
3 years ago
The length of a rectangle is 5cm. greater than its width. The perimeter is 58 cm. Find the dimensions of the rectangle.
lidiya [134]
w-the\ width\\l=w+5-the\ length\\\\\\The\ perimeter\ of\ rectangle:P=58cm\\\\P=2w+2l\\\\2w+2(w+5)=58\\2w+2w+10=58\\4w+10=58\ \ \ \ |subtract\ 10\ from\ both\ sides\\4w=48\ \ \ \ \ |divide\ both\ sides\ by\ 4\\w=12\ (cm)\\\\l=12+5=17\ (cm)\\\\Answer:The\ dimensions\ of\ the\ rectangle:17cm\times12cm
8 0
3 years ago
Read 2 more answers
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