Answer:
Given:
Diameter = 38cm
Radius = Diameter /2
Radius = 38 / 2
Step-by-step explanation:
Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.
Answer: non-linear 40 1/2 Step-by-step explanation: This is a non-linear function specifically it is an oscillating function The initial position of the weight occurs at t=0 and from the graph we see that at t=0, the weight position is 40 centimeters The weight is said to reach equilibrium when its position is at 0 cm. From the graph we can see that the function first reaches 0 cm at t=0.5 seconds or at t= 1/2 second
Find the horizontal and vertical distance between the points. First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.