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Jobisdone [24]
3 years ago
7

an architect designs a rectangular flower garden such that the width is exactly two thirds of the length. if 230 feet of antique

picket fencing are to be used to enclose the garden, find the dimensions of the garden.
Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

<h2>length = 69 ft.</h2><h2> width = 46 ft.</h2>

Step-by-step explanation:

perimeter (p) = 2L + 2W

where P = 230 ft.

W = 2/3L

plugin values into the formula:

230 = 2L + 2(2L/3)

230 = 2L + 4/3L

230 = 10/3L

L = 690/10

L = 69

W = 2/3L

W = (2/3) 69

W = 46

P = 2(69) + 2(46)

P = 230 ft.

therefore,

the dimensions of the rectangular garden:

length = 69 ft

width = 46 ft.

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Find the equation of the line with slope = -4 and passing through (9,-29). Write your equation in the form
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Answer:

y = -4x + 7

Step-by-step explanation:

As we can see, we want to write the equation of the line

we have this as;

y = -4x + b

To get the y-intercept, we use the values in the point given

we substitute x = 9 and y = -29

So we have;

-29 = -4(9) + b

-29 = -36 + b

b = 36-29

b = 7

So the equation is;

y = -4x + 7

8 0
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Convert the following into Vertex form<br> y=-3x^2 +1
olganol [36]
I suck at explaining but I know it’s 4
6 0
2 years ago
- y - 10 = 6x <br> 5x + y = - 10
Inga [223]

Answer:

(0,-10)

Step-by-step explanation:

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5 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
Here is a list of numbers 2 17 1 13 7 18 14 18 20 state the median
Ivan

Answer:

14

Step-by-step explanation:

median is the number in the very middle when the numbers are organized in order:

1, 2, 7, 13, 14, 17, 18, 18, 20

if we start taking away from both ends we’ll get the answer

2, 7, 13, 14, 17, 18, 18

7, 13, 14, 17, 18

13, 14, 17

14

5 0
3 years ago
Read 2 more answers
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