9514 1404 393
Answer:
2
Step-by-step explanation:
We assume your recursive formula is ...

Using this to find a4, we get ...

<u>Answer:</u>
A. y = -2 - cos(x-π)
<u>Explanation:</u>
<u>The general form of the trig equation is:</u>
y = A sin (Bx + C) + D
where:
A is the amplitude
is the period
is the phase shift
D is the vertical shift
<u>Now, let's check the choices:</u>
<u>A. y = -2 - cos(x-π)</u>

Therefore, the function has a phase shift of π
<u>B. y = 3 cos(4x)</u>

Therefore, the function has no phase shift
<u>C. y = tan(2x)</u>

Therefore, the function has no phase shift
<u>D. y = 1 + sin(x)</u>

Therefore, the function has no phase shift
<u>Based on the above,</u> the correct answer is A
Hope this helps :)
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
I think it is a trick question but um the lanth is hight times 3/4