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Natasha_Volkova [10]
3 years ago
6

60 boys at a summer camp were asked to complete a survey about their favorite outdoor activity. 18 boys chose biking and 29 boys

chose fishing. The remaining boys did not complete the survey. Which expression gives the percent of survey participants who chose fishing?
Mathematics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

 Expression for percent of survey participants who chose fishing = \frac{29}{47} *100

Explanation:

 Total number of boys = 60

 Number of boys who took part in survey = 18 + 29 =47

 Number of boys who chose fishing = 29.

 Percentage of an outcome = (Number of favorable outcome/ Total number of outcome) x 100

 Percentage of boys who chose fishing = (29/47)x100

 Expression for percent of survey participants who chose fishing = \frac{29}{47} *100



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I hope that helped u
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What is the area of the kite?<br> 6 ft<br> 14 ft
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Step-by-step explanation:

if these are diagonals ,then

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Based on information from Harper’s Index, 37% of adult Americans believe in Extraterrestrials. Out of a random sample of 100 adu
san4es73 [151]

Answer:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

Step-by-step explanation:

We have a prortion test.

P₀  =  37 %         P₀  = 0,37

sample size  =  n  =  100

P sample proportion   =   P  = 47 %        P  =  0,47

confidence interval  95 %

α  =   0,05  

One tail-test  (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.

1.-Hypothesis:

H₀      null hypothesis                        P₀  =  0,37

Hₐ  alternative hypothesis                P₀  >  0,37

2.-Confidence interval 95 %

α  =   0,05        and    z(c)  =  1.64

3.-Compute of z(s)

z(s)  =  [  P  -  P₀  ]  /√(P₀Q₀/n) ]  

z(s)  =  [ (  0,47  -  0,37  ) /  √0.37*0,63/100

z(s)  = 0,1 /√0,2331/100     ⇒   z(s)  = 0,1 /0,048

z(s)  = 2.08

4.-Compare  z(s)   and  z(c)

z(s) > z(c)        2.08  > 1.64

5.-Decision:

z(s)  is in the rejection zone , therefore we reject H₀

We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%

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Answer:

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Step-by-step explanation:

\frac{ {x}^{2} +  {y}^{3}  }{2 + x}  \\

when,

x = 6 \\ y = 2

Now substitute the value we get,

\frac{ {6}^{2}  +  {2}^{3} }{2 + 6} \\  \\  =  \frac{36 + 8}{8}   \\  \\  =  \frac{44}{8} \\  \\  =  \frac{11}{2}

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