Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

Indefinite integral of the expression will be $16lnx+16x$

Step-by-step explanation:

We have given expression $I=\int( \frac{16}{\sqrt{x^2}}+16)dx=\int (\frac{16}{x}+16)dx$

We have to integrate this function

So I=\int( \frac{16}{\sqrt{x^2}}+16)dx=\int (\frac{16}{x}+16)dx=\int (16x^{-1}+16)dx

$I=\int (16x^{-1}+16)dx=16lnx+16x$

So indefinite integral of the expression will be $16lnx+16x$

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