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Ugo [173]
3 years ago
5

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

Indefinite integral of the expression will be 16lnx+16x

Step-by-step explanation:

We have given expression I=\int( \frac{16}{\sqrt{x^2}}+16)dx=\int (\frac{16}{x}+16)dx

We have to integrate this function

So I=\int( \frac{16}{\sqrt{x^2}}+16)dx=\int (\frac{16}{x}+16)dx=\int (16x^{-1}+16)dx

I=\int (16x^{-1}+16)dx=16lnx+16x

So indefinite integral of the expression will be 16lnx+16x

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