Step-by-step explanation:
Let x be the length of segment AB.
Then the length of segment BC is (2x - 4).
The length of segment AC is x.
We know that x + (2x - 4) + x = 52.
Therefore 4x - 4 = 52, 4x = 56, x = 14.
Hence the length of segment AB is 14.
Answer:
50,000 miles
Step-by-step explanation:
First,
If C is the annual operating cost, you can modify/substitute into the equation,
21,100 = 0.37m + 2600
Second, solve the equation for m,
0.37m = 18,500
m = 50,000
Hope this helps!!
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If they give you the total price and the price after the discount you can use this "formula" to solve it p/100=b/a where p is the percentage, a is the total price and b is the price after the discount.
0.03x+0.06 (6500-x)=225
Solve for x
0.03x+390-0.06x=225
0.03x-0.06x=225-390
-0.03x=-165
X=165÷0.03
X=5500 invested at 3%
6500-5500=1000 invested at 6%
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
