I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is
x+1=0; x+1=0
In this case, the factors are the same so the root of the equation is
x=1.
The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
Plug in x = 7. Then use the order of operations (PEMDAS) to simplify
y = 11 - 5*x
y = 11 - 5*7 .... x has been replaced with 7 (since x = 7 is given)
y = 11 - 35
y = -24
Answer:
D
Step-by-step explanation:
First of all, i mean A and B are out first thing because you don't have enough information to find out if it's true.
C is incorrect because as stated before, not enough information.
<u><em>However,</em></u>
You know that the angles 1-8 are all supplementary, which means that 1 and 2 can be added to make 180 degrees, as so can 3 and 4, 3 and 1. 2 and 4, blah blah blah.
In D, the angles that are being added are supplementary, because the three lines making up that weird figure is adjacent and is parallel to each other.
If you give one of the angles a degree, you know that 180-x with x being that degree, will equal the other angle on the other side of the lines.
Therefore its D.
Edit:
I just realized that theres an angle stated at the top of the screen. Still with that angle given, A and B is incorrect and the answer is still D.
Answer:
221.87 feet
Step-by-step explanation:
Given that,
A 525 ft cable runs from the top of an antenna to the ground.
The angle of elevation made by the ground to the top of an antena 25°
We need to find the height of the antenna.
Using trigonometry,
Hypotenuse, H = 525 ft
θ = 25°
So,
So, the height of the antenna is equal to 221.87 feet.
I believe the answer to this30+5+.2+.04+.005
