All categories

3 years ago

What is the answer to 2m-6=48

Mathematics

1 answer:

Marrrta [24]3 years ago

5 0

2m-6=48
+6 +6
__________
2m= 42
÷2 ÷2
_________
m=21

m=21 is the answer

You might be interested in

Given that sec theta= -37/12, what is the value of cot theta , for pie/2 < theta< pie?

Triss [41]

The answer is B. Thank me in the future!

always remember ~Positive Vibes~

6 0

3 years ago

Read 2 more answers

The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the

ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/ $\sqrt{n}$ )

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/ $\sqrt{n}$

The upper limit => C.I_u = μ + Z*σ/ $\sqrt{n}$

The lower limit => C.I_l = μ - Z*σ/ $\sqrt{n}$

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/ $\sqrt{n}$ )

= 200 + (1.96*30)/ $\sqrt{n}$

= 200 + 58.8/ $\sqrt{n}$

5 0

3 years ago

What is the surface area of a cylinder with a diameter of 8 centimeters and a height of 12 centimeters?

Lostsunrise [7]

The formula for this is $A=2 \pi rh+2 \pi r^{2}$ . If the diameter is 8 the radius is 4, so filling in accordingly we have $A=2 \pi (4)(12)+2 \pi (16)$ and $A=96 \pi +32 \pi$ which is $A=128 \pi$ and when you multiply in 3.14 you get that A = 401.92 or B above.

8 0

3 years ago

Write each polynomial function in standard form , classify it by degree and determine the end behavior of its graph Y=12-x^4

Dmitry_Shevchenko [17]

In standard form, zero is always on the right:
y = 12 - x^4
y + x^4 - 12 = 0

End behavior:
As x approaches ∞, y approaches -∞
As x approaches -∞, t approaches -∞

4 0

3 years ago

Write an explicit formula for the recursive formula <br><br> A(n) = A(n - 1) + 3; A(1) = 6

arsen [322]

Answer:

$a_{n}$ = 3n + 3

Step-by-step explanation:

The sequence is arithmetic with explicit formula

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

From the recursive formula

a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then

$a_{n}$ = 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3

7 0

2 years ago