Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
Answer:
1 - cosΘ
Step-by-step explanation:
using the identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x
= 
← factor 1 - cos²Θ as a difference of squares
= 
← cancel 1 + cosΘ on numerator/ denominator
= 1 - cosΘ
Do you just want the answer or do you need the work too??
4x - 2 = 2x + 8
2x -2 = 8
2x = 10
x = 5
4(5)-2 = 2(5)+8
20-2 = 10+8
18 = 18
The answer is 31/40
because first you got cane both of the fraction to the same denominator.
72/80 + 70/80
Add 72+70=142.
142/80 change it to an mixed number and it will be 1 31/40 in simplest form.
