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Tcecarenko [31]
4 years ago
5

A florist is making flower arrangements with 32 roses and 40 tulips. Each arrangement must be identical. What is the greatest nu

mber of arrangements the florist can make if all of the flowers are used?
Mathematics
1 answer:
Aleks04 [339]4 years ago
8 0
We must find the greatest common factor so we can see what is the biggest number we can divide both numbers into so
find the factors
32=2 times 2 times 2 times 2 times 2
40=2 times 2 times 2 times 5
gcf=2 times 2 times 2=8
the answer is 8
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What is the next term in the following constant velocity sequence? 10 cm, 16 cm, 22 cm, ...
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The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the
sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}

When we use this to replace the 't" in the displacement formula, we et:

y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity v_0 , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0
3 years ago
You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. Th
solmaris [256]

Let's assume

length of rectangle =L

width of rectangle =W

You enclose 3 sides of the garden with 40 feet of fencing

so, we get

L+2W=40

now, we can solve for L

L=40-2W

we know that

area of rectangle is

A=L*W

100=L*W

now, we can plug

100=(40-2W)*W

now, we can solve for W

-2W^2+40W-100=0

we can use quadratic formula

W=\frac{-40+\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

W=\frac{-40-\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

we can take anyone value ..because both are giving positive value

first dimensions:

W=2.929

now, we can find L

L=40-2*2.929

L=34.142

so, length is 34.142feet

width is 2.929 feet

Second dimensions:

W=17.071

now, we can find L

L=40-2*17.071

L=5.858

so, length is 5.858feet

width is 17.071 feet



6 0
3 years ago
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