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4 years ago

Which situation can be represented by the 40x + 20 = 200?

Mathematics

1 answer:

garik1379 [7]4 years ago

4 0

Answer: The first situation fit the equation and it will take Mitch 4.5 weeks to pay back

Step-by-step explanation:

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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

3 years ago

ivan and polina have each drawn a conclusion about multiplying negative fractions. Ivan: The products of an even number of negat

vladimir2022 [97]

Answer:

Both are correct

-1 x -1 = 1

-1 x -1 x -1 = -1

Hope this helps

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Anybody know the answer?

Andreas93 [3]

Answer: The slope of the line is m, which is 3.

Step-by-step explanation:

Don’t mind the two parts I scribbled out, I didn’t a few extra steps when I misread the instructions. Just look at the top left corner and the right side of how I solve for the slope.

7 0

2 years ago

Let f and g be the functions defined by f(x) = 10^ (x+2 / 3) and g(x) = log (x3 / 100) for all positive real numbers,

Vaselesa [24]

Answer:

F(x) and g(x) are not inverse functions.

Step-by-step explanation:

In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.

As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.

$[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x$ [/tex]

Now we change the variables.

$F(x)=log x-\frac{2}{3}$

F(x) and g(x) are not inverse functions.

4 0

3 years ago

When both parties discuss the terms of a contract they are

marysya [2.9K]

B - Negotiating.

This is because they are communicating, they haven't yet agreed to anything or committed to the contract as neither parties have signed, thus leading to both C and D to be incorrect.

A, however, is not exactly a term used for this situation - contracting is more of a term used to say someone contracted a disease or the flu or etc.

Therefore, B would be correct as they are indeed negotiating the terms of the contract.

Hope this helps!

7 0

4 years ago