Answer:
Fifth graders= 93 shirts
Sixth graders= 156 shirts
Teachers= 51 shirts
Step-by-step explanation:
31% of 300 is 93
52% of 300 is 156
The total number of shirts sold to fifth graders and sixth graders is:
156+93= 249
The number of shirts sold to teachers is:
300-249= 51
Answer:
1) C) sin(θ) = 119/169
2) D) cos(θ) = 120/169
Step-by-step explanation:
The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.
Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1
Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2
Answer:
y = 2x+10
Step-by-step explanation:
y is the cost (which we don't know)
2x is the $2 per card with x representing the number of cards (which we don't know)
And of course 10 is the cover charge.
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:
Solve for x
Subtract 8x from both sides
Add 11 to both sides
Divide both sides by 2
2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Answer:
See step by step
Step-by-step explanation:
For A. use any two factors that multiply to 100 that isn't 25 and 4.
For b Use one obtuse angle (angle over 90 degree) and two acute angles. Make sure they add up to 180.
For c Use any two values that add up to 52 since they didnt establish y as the midpoint.
For d. measure of angle 1 is 45 and measure of angle 2 is 45 degrees
