Answer:
1. f(x)=4 sin (2 x-π)-1
=4 sin [-(π-2 x)] -1
= -4 sin 2 x -1
-1 ≤ sin 2 x ≤1
f(x) is minimum, when, sin 2 x=1
= -4 × 1 -1
= -5→Minimum value of f(x).
2. Minimum y value of g(x) by looking at the table is ,
g(x)=-3→Minimum
3. h(x)=(x-2)²+4
As, (x-2)², will yield always a positive value.
So, minimum of h(x), will be at , x=2
h(2)=(2-2)²+4=4→Minimum
Among the three function given, f(x) has minimum y -value,equal to -5.
Option A: f(x)
