64cm2 converted into millimeters is 6400mm2
<span>4.8 (x+4)=2.6
Use distributive property
4.8x + 19.2= 2.6
Subtract 19.2 from both sides
4.8x = -16.6
Divide 4.8 on both sides so that the only thing remaining on the left side is the variable x.
Final Answer: x = -3.458</span>
Solution:
We are going to find the distance between points A -4; 2, B 3; -5 :
d = √ (xb - xa) 2 + (yb - ya) 2 =
= √ (3 - (-4)) 2 + (-5 - 2) 2 =
= √72 + (-7) 2 = √49 + 49 =
= √98
= 7√2 ≈ 9.899494936611665
Answer:
Δ MLP ~ Δ HKG
By S-A-S similarity Postulate.
Step-by-step explanation:
Given:
In Δ MLP
MP = 20 ,
LP = 15
∠ P = 42°
In Δ HKG
HG = 16 ,
KG = 12
∠G = 42°
To Prove:
Δ MLP ~Δ HKG
Proof:
In Δ MLP and Δ HKG
..........( 1 )
..............( 2 )
∴
...From 1 and 2
∠P ≅ ∠ G = 42° ...............Given
∴ Δ MLP ~Δ HKG ......{ By S-A-S similarity test}............Proved
A':(-2,-4)
B':(-7,-6)
C':(-1,-13)
I've done the test before