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Lena [83]
4 years ago
15

A library expansion, begun in 2002, was expected to cost $103 million. By 2006, library officials estimate the cost would be $39

million over budget. By what percent did the actual cost exceed the initial estimate? Please show the work so I can figure out how to do the question.
Mathematics
1 answer:
Rainbow [258]4 years ago
6 0

initial estimate in 2002 = 103M

Actual cost in 2006 = 142M  (103M + 39M)

% over budget = 39/103 = 37.86%

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Answer:

{13.7756,18.2244}

Step-by-step explanation:

Given the sample size, the margin of error can be calculated with the formula M=Z*\frac{\sigma}{\sqrt{n}} where Z is the critical value for the desired confidence level, σ is the population standard deviation, and n is the sample size. Therefore, our margin of error for a 90% confidence level is:

M=Z*\frac{\sigma}{\sqrt{n}}=1.645*(\frac{8}{\sqrt{35}})=2.2244

The formula for a confidence interval is CI=\bar{x}+M where x-bar is the sample mean. Therefore, the 90% confidence interval for the mean amount of sushi pieces a person can eat is:

CI=\bar{x}\pm[M]=16\pm2.2244={13.7756,18.2244}

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Vitek1552 [10]

<em>Note: I am assuming we have to determine the angle 'Ф'.</em>

Answer:

The value of Ф = 22.6°

Step-by-step explanation:

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