Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:

Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000

1 Second prize $450

10 Third prize $25

No prize -$4

TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
Answer:
3 1/6
Step-by-step explanation:
To find the highest value, we have to evaluate each term individually,
1) 1 1/6 = 7/6 = 1.167
2) 3 1/6 = 19/6 = 3.16
3) 3/8 = 0.375
4) 5/8 = 0.625
Therefore, second data value (3 1/6) is highest.
Answer:
C
Step-by-step explanation: