I think the answer is C-No solutions
Answer:
The x is the domain and the y is the range. It's still a function
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
x² - 12x + 11 = 0 ( subtract 11 from both sides )
x² - 12x = - 11
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 6)x + 36 = - 11 + 36
(x - 6)² = 25 ( take square root of both sides )
x - 6 = ± 
= ± 5 ( add 6 to both sides )
x = 6 ± 5
Then
x = 6 - 5 = 1 ⇒ (1, 0 )
x = 6 + 5 = 11 ⇒ (11, 0 )
Answer:
So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.
y-y = (3x+7)-(-2x-3) =
0 = 3x+7+2x+3
0 = 5x+10
-10 = 5x
-2 = x.
Now we need to solve for y.
Plug it in for the first equation. -2*3+7 = -6+7 = 1
Test if we are correct and try in the second equation.
-2*-2-3 = 4-3 = 1
<u>x = -2</u>
<u>y = 1</u>
