10. 4,200 cm
This is the correct answer!
10 + 50 = 60
£1.00 convert into indian paise = 83p
10+50+83=143
Answer:
The distance between two points (x₁, y₁) and (x₂, y₂) is given by:
![d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D)
Now we know that point D, which we can write as (x, y), is at a distance of 8 units from the origin.
Where the origin is written as (0, 0)
We also know that point D is 6 units away along the y-axis.
Then point D could be:
(x, 6)
or
(x, -6)
Now, let's find the x-value for each case, we need to solve:
![8 = \sqrt{(x - 0)^2 + (\pm6 - 0)^2}](https://tex.z-dn.net/?f=8%20%3D%20%5Csqrt%7B%28x%20-%200%29%5E2%20%2B%20%28%5Cpm6%20-%200%29%5E2%7D)
notice that because we have an even power, we will get the same value of x, regardless of which y value we choose.
![8 = \sqrt{x^2 + 36} \\\\8^2 = x^2 + 36\\64 - 36 = x^2\\28 = x^2\\\pm\sqrt{28} = x\\\pm 5.29 = x](https://tex.z-dn.net/?f=8%20%3D%20%5Csqrt%7Bx%5E2%20%2B%2036%7D%20%5C%5C%5C%5C8%5E2%20%3D%20x%5E2%20%2B%2036%5C%5C64%20-%2036%20%3D%20x%5E2%5C%5C28%20%3D%20x%5E2%5C%5C%5Cpm%5Csqrt%7B28%7D%20%20%3D%20x%5C%5C%5Cpm%205.29%20%3D%20x)
So we have two possible values of x.
x = 5.29
and
x = -5.29
Then the points that are at a distance of 8 units from the origin, and that are 6 units away along the y-axis are:
(5.29, 6)
(5.29, -6)
(-5.29, 6)
(-5.29, -6)
Answer:
4$
Step-by-step explanation:
6A + 4(14) = 80
6A + 56 = 80
6A = 24
A = 4
9.72÷7 = 1.3885 .so nearest cent is 1.39