Diagonal of the rectangular prism=√(l²+w²+h²)
√(l²+w²+h²)=√(100+25+64)=√189 cm
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>
Step-by-step explanation:
<em><u>Given</u></em><em><u>,</u></em>
No. of families = 75
Out of 75 no. of families had cars = 42
Out of 1, no. of families can have cars
![= \frac{42}{75}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B42%7D%7B75%7D%20)
<em><u>Therefore</u></em><em><u>, </u></em>
Out of 200 families, no. of families had cars
![= 200 \times \frac{42}{75}](https://tex.z-dn.net/?f=%20%3D%20200%20%5Ctimes%20%20%5Cfrac%7B42%7D%7B75%7D%20)
![=200 \times \frac{14}{25}](https://tex.z-dn.net/?f=%20%3D200%20%5Ctimes%20%20%20%5Cfrac%7B14%7D%7B25%7D%20)
= 8 × 14
= 112
<em><u>Hence</u></em><em><u>, </u></em>
<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer:
Angle bisector
Step-by-step explanation:
median isn't applicable in this case as the roads from the streets are inclined at an angle.
altitude refers to height which is also not applicable
The perpendicular bisector is the locust of points equidistant from two points,
in this question the street are not seen as points but as lines which forms an angle and the bisection of this angle forms a locus where she can park her car. If she parks her car anywhere on the angular bisector of the two streets, she would be at equal distance from both streets.
Answer: 250 miles per inch
Step-by-step explanation: