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Alisiya [41]
2 years ago
9

PLEASE HELP!! 20 POINTS

Mathematics
2 answers:
Anarel [89]2 years ago
5 0
The width of the triangle would be the answer C) 0 in
Nat2105 [25]2 years ago
5 0
The answer is 9 inches. 

9 + 2 = 11
9 x 11 = 99


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Can some one explain how to answer this
Softa [21]
You would first have to find the area of the other part.

6 0
3 years ago
Help plz I really don't get it
AURORKA [14]
You answered would be n is greater or equal to 4 but u have to us that symbol
4 0
3 years ago
3 An open cone has a vertical angle measuring 40°
belka [17]

Answer:

13.41 cm

Step-by-step explanation:

The radius, height, and HALF of vertical angle makes a triangle.

Where

Radius will be the base of the triangle

Height will be the "height" of the triangle

Top angle will be HALF of vertical angle (40/2 = 20)

From the 20 degree angle, the side "opposite" would be the radius, which is 30. The side "adjacent" would be the height, let it be h.

<em>Which trig ratio relates opposite and adjacent? Yes, that is TAN. Thus we can write:</em>

Tan(20) = opposite/adjacent

Tan(20) = 30/h

h = 30/Tan(20)

h = 13.41

So

The height of the cone would be around 13.41 cm

3 0
3 years ago
In a parking lot with 250 parking spaces 40% how many of them are vacant and occupied
Darina [25.2K]
If that 40% is how many are occupied then- 100 are occupied 150 are vacant
if that 40% is how many are vacant then- 100 are vacant and 150 are occupied
3 0
2 years ago
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
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