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3 years ago

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How much money will there be in an account at the end of 8 years if $9,000 is deposited at 3% interest compounded semi-annually?

(Assume no withdrawals are made.)

1 answer:

Dafna11 [192]3 years ago

8 0

Answer:

8730

Step-by-step explanation:

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4 years ago

Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

3 years ago

Read 2 more answers

A study of college business majors included 150 sophomores and 200 juniors. The study showed that 80 sophomores and 150 juniors

vlabodo [156]

Answer:

0.3478

Step-by-step explanation:

Given:-

- The number of sophomore, S = 150

- The sophomore and had summer internship, x = 80

- The number of juniors, J = 200

- The junior and had summer internship, y = 150

Find:-

What is the probability that the person is a sophomore given that the person had a summer internship?

Solution:-

- The total sum of sophomore and junior students is N:

N = S + J

N = 150 + 200

N = 350 students.

- We will denote event A as random selection of sophomore from total.

- We will denote event B as random selection of student who had summer internship.

- We are to determine the conditional probability that a person selected is sophomore given that the person had a summer internship. That is the probability of event A given that event B has already occured.

- The conditional probability can be written as:

P ( A / B ) = P ( A & B ) / P ( B )

Where,

P ( A & B ) : The probability the person is a sophomore and had a summer internship.

P ( B ): The probability that the person selected had a summer internship.

P ( A & B ) = x / N

= 80 / 350

= 0.22857143

P ( B ) = ( x + y ) / N

= ( 80 + 150 ) / 350 = 230/350

= 0.65714286

Therefore the required probability is:

P ( A / B ) = 0.22857143 / 0.65714286

= 0.3478 ... Answer

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