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guapka [62]
3 years ago
7

If 5^3 b-1=5^b-3, what is the value of b?

Mathematics
1 answer:
kondaur [170]3 years ago
3 0
Let's solve your equation step-by-step.<span><span><span><span>(<span>53</span>)</span><span>(b)</span></span>−1</span>=<span><span>5b</span>−3</span></span><span><span><span>125b</span>−1</span>=<span><span>5b</span>−3</span></span>Step 1: Flip the equation.<span><span><span>5b</span>−3</span>=<span><span>125b</span>−1</span></span>Step 2: Add 3 to both sides.<span><span><span><span>5b</span>−3</span>+3</span>=<span><span><span>125b</span>−1</span>+3</span></span><span><span>5b</span>=<span><span>125b</span>+<span>2
I cant go more its impossible mark me as brainless please!!</span></span></span>
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\displaystyle\\&#10;1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ &#10;1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ &#10;-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ &#10;-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


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7 0
3 years ago
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4 0
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0.6(4-2x)=20.5-(3x+10)
solong [7]

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation  

\rightarrow 0.6(4-2 x)=20.5-(3 x+10)

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10

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Now subtraction is done

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