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2 years ago

If 5^3 b-1=5^b-3, what is the value of b?

1 answer:

3 0

Let's solve your equation step-by-step.(53)(b)−1=5b−3125b−1=5b−3Step 1: Flip the equation.5b−3=125b−1Step 2: Add 3 to both sides.5b−3+3=125b−1+35b=125b+2
I cant go more its impossible mark me as brainless please!!

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At which value(s) of x does the graph of the function F(x) have a vertical asymptote? Check all that apply.

Mars2501 [29]

Answer:

-2 is the only correct answer

4 0

2 years ago

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Which of these equations have no solution? check all that apply

finlep [7]

Answer:

A, B, and E

Step-by-step explanation:

Let's look through each of the answer choices.

A) 2(x + 2) + 2 = 2(x + 3) + 1

Simplify this by expanding out the parentheses:

2x + 2 * 2 + 2 = 2x + 2 * 3 + 1

2x + 4 + 2 = 2x + 6 + 1

2x + 6 = 2x + 7

6 = 7

Well, we know that 6 is NOT equal to 7, so this has no solutions.

B) 2x + 3(x + 5) = 5(x – 3)

Simplify this by expanding out the parentheses:

2x + 3x + 3 * 5 = 5x - 5 * 3

5x + 15 = 5x - 15

15 = -15

Again, we know that 15 is NOT equal to -15, so this also has no solutions.

C) 4(x + 3) = x + 12

Simplify this by expanding out the parentheses:

4x + 4 * 3 = x + 12

4x + 12 = x + 12

3x = 0

x = 0

This actually does have a solution when x = 0, so eliminate this.

D) 4 – (2x + 5) = (–4x – 2)

Simplify this by expanding out the parentheses:

4 - 2x - 5 = -4 - 2

-2x - 1 = -6

-2x = -5

x = 2.5

This also has a solution when x = 2.5, so eliminate this.

E) 5(x + 4) – x = 4(x + 5) – 1

Simplify this by expanding out the parentheses:

5x + 5 * 4 - x = 4x + 4 * 5 - 1

4x + 20 = 4x + 19

20 = 19

Here, we know that 20 is NOT equal to 19, so this has no solution.

Hope this helps!

8 0

2 years ago

Read 2 more answers

Hey so i need help on my khan so please please please help

Lana71 [14]

Answer:

Step-by-step explanation:

4 0

2 years ago

PLEASE HELP ME WITH THIS I WILL MARK BRAINLIEST!! Classify each system of equations as having a single solution, no solution, or

Wewaii [24]

Answer:

see the explanation

see the attached figure

Step-by-step explanation:

Part 1) we have

$y=11-2x$ ----> equation A

$4x-y=7$

Isolate the variable y

$y=4x-7$ ----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 2) we have

$x=12-3y$

isolate the variable y

$y=-(1/3)x+4$ -----> equation A

$3x+9y=24$

isolate the variable y

$y=-(1/3)x+(8/3)$ ----> equation B

Compare equation A and equation B

The slopes are equal

The y-intercept are different

That means

we have parallel lines with different y-intercept

The lines don't intersect

therefore

The system has no solution

Part 3) we have

$2x+y=7$

isolate the variable y

$y=-2x+7$ -----> equation A

$-6x=3y-21$

isolate the variable y

$y=-2x+7$ ----> equation B

Compare equation A and equation B

The equations are identical

That means

Is the same line

The system has infinitely solutions

Part 4) we have

$x+y=15$

isolate the variable y

$y=-x+15$ -----> equation A

$2x-y=15$

isolate the variable y

$y=2x-15$ ----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 5) we have

$2x+y=7$

isolate the variable y

$y=-2x+7$ -----> equation A

$-4x=2y+14$

isolate the variable y

$y=2x-7$ ----> equation B

Compare the slope of both lines

The slopes are different

That means

The lines intersect at one point

therefore

The system has one solution

Part 6) we have

$x+4y=6$

isolate the variable y

$y=-0.25x+1.5$ -----> equation A

$2x=12-8y$

isolate the variable y

$y=-0.25x-1.5$ ----> equation B

Compare equation A and equation B

The slopes are equal

The y-intercept are different

That means

we have parallel lines with different y-intercept

The lines don't intersect

therefore

The system has no solution

6 0

2 years ago

Find the coordinates of the points of trisection of the line segment joining the points (3, – 2) and (– 3, – 4).

Hatshy [7]

Let us suppose the given points are A (3, – 2) and B(– 3, – 4).

Let P and Q be the point of trisection. Therefore, we have

$AP=PQ=QB$

Trisection means is to divide a line segment into three equal parts. Hence, we can say that P divides AB in the ratio of 1:2 and Q divides in 2:1 .

Thus, coordinate of P is given by

$P=(\frac{mx_2+nx_1}{m+n} ,\frac{my_2+ny_1}{m+n})\\
\\
P=(\frac{1\times (-3)+2\times 3}{1+2} , \frac{1\times (-4)+2\times (-2)}{1+2} )\\
\\
P=(\frac{-3+6}{3} ,\frac{-8}{3} )\\
\\
P=(1,-\frac{8}{3} )$

Similarly the coordinate of Q is given by

$Q=(\frac{2\times (-3)+1\times 3}{1+2} , \frac{2\times (-4)+1\times (-2)}{2+1} )\\
\\
Q=\left (\frac{-6+3}{3},\frac{-8-2}{3} \right )\\
\\
Q=\left ( \frac{-3}{3},-\frac{10}{3} \right )\\
\\
Q=\left ( -1,-\frac{10}{3} \right )$

Therefore, the coordinates of the point of trisection are

$(1,-\frac{-8}{3})\text{ and }\left ( -1,-\frac{10}{3} \right )$

7 0

2 years ago