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Ierofanga [76]
3 years ago
5

Find the mean of the data: 14, 9, 2, 13, 16, 3, 13, 10

Mathematics
1 answer:
svp [43]3 years ago
7 0
<span>14+ 9 + 2+ 13+ 16+3+ 13+ 10 = 80
80/8 = 10

answer
mean = 10

</span>
You might be interested in
Which set of ratios could be used to determine if one triangle is a dilation of the other
Lisa [10]

Answer:

See explanation

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

Step-by-step explanation:

The two triangles are similar if the ratio of the corresponding sides are proportional.

The ratio of the corresponding sides are:

\frac{3.6}{3}  = 1.2

\frac{5.4}{4.5}  = 1.2

\frac{6}{5}  = 1.2

The set of ratios which could be used to determine if one triangle is a dilation of the other is

\frac{3.6}{3}  =  \frac{5.4}{4.5}  =  \frac{6}{5}

If there are multiple correct options then check this one too.

\frac{3}{3.6}  =  \frac{4.5}{5.4} =  \frac{5}{6}

3 0
3 years ago
A newborn child receives a $5000 gift toward a college education from her grandparents. How much will the $5000 be worth in 20 y
igomit [66]

Step-by-step explanation:

5000:100=50

50×7,3=365

365×20=7,300$

3 0
3 years ago
Find the missing number 9:4::63: ?
gulaghasi [49]

Answer: 28

Step-by-step explanation:

28 is thhe missing number

4 0
1 year ago
Which of the following is the slope of the line<br> A. -3<br> B. 1/3<br> C. -1/3<br> D. 3
Crazy boy [7]

A

Ask if explanation needed :)


6 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
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