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kirill [66]
3 years ago
13

A boat has a top speed of 4949 knots​ (nautical miles per​ hour). what is this speed in miles per​ hour?

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
The answer is 2545.98556 m / s
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SOMEONE PLEASE HELP ME!!! I REALLY NEED SOME HELP!!!
Lostsunrise [7]

Answer:

A. (1, -2)

Step-by-step explanation:

We can substitute the variables of x and y into the inequality of y < -|x|.

Let's start with A, -2 being y and 1 being x.

-2 < - |1|

The absolute value of 1 is 1, and negating that gets us -1.

-2 < -1

Indeed, -2 is less than -1! So A is a solution to the inequality.

Let's test the rest of them, just in case.

For B:

-1 < -|1|

Absolute value of 1 is 1, negating it is -1.

-1

-1 is EQUAL to -1, not less than it, so is not a solution to the inequality.

Let's try C.

0 < -|1|

Absolute value of 1 is 1, negating it is -1.

0 < -1

0 is GREATER than -1, so that is not a solution to the inequality.

Hope this helped!

4 0
3 years ago
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
When writing twenty-one-and-a-half-trillion in scientific notation, what is the exponent needed on the base ten?
Nat2105 [25]
1 trillion is 10^9.

Thus, 21 1/2 trillion is    21 1/2 times 10^9, or 2.15 times 10^10

Hope this helps.  If not, ask for clarification.
5 0
3 years ago
Read 2 more answers
Round to the nearest tenth<br> 18 is what percentage of 79
GenaCL600 [577]
79 multiply .18 and you’ll get your answr
6 0
3 years ago
Caitlin has 4 and 3/4 lb of place use 1 1/10 pound to make a cup and another 2 pounds to make a jar how many pounds are left
g100num [7]
We know that
4 3/4---------> (4*4+3)/4----------> 19/4
1 1/10-----------> (10*1+1)/10----> 11/10

[pounds left]=[(19/4)-(11/10)-(2)]----> (10*19-4*11-40*2)/40
=(190-44-80)/40-------> 66/40---------> 1.65 pounds
1.65-----> 1 65/100--------> 1 13/20 pounds

the answer is 1.65 pounds  (1 13/20 pounds)


7 0
3 years ago
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