The top two ?
1. 0, 0.2, '0.4, 0.6, 0.8, 1.0, 1.2, 1.4', 1.6
2. 0, 0.5, '1.0, 1.5, 2.0, 2.5', 3.0
Answer:
See explanation
Step-by-step explanation:
The triangles below are congruent and their corresponding parts are marked.
a) Angles marked with one arc are congruent, so 
Angles marked with two arcs are congruent, so 
Angles marked with three arcs are congruent, so 
b) Sides marked with one segment are congruent, so 
Sides marked with two segments are congruent, so 
Sides marked with three segments are congruent, so 
c) Name teo congruent triangle following the congruence of angles:
This form (x+b)²+c is a vertex form that can be found by completing square for the equation <span>x²+440x+440².
To complete square we will need to use formula a² +2ab + b² = (a+b)²
</span> x²+440x+440²,
<span>x² +2*220²x +220² -220² +440² (we added </span>220² -220², so nothing really changed here).
x² +2*220²x +220² -220² +440² ( here , bold part can be rewritten as (x+220)²)
(x+220)² -220² +440² (calculating bold part)<span>
</span>(x+220)² -220² +440² = (x+220)² + 145200
Now we have x²+440x+440², in the form that we need
x²+440x+440² = (x+220)² + 145200
(x+b)²+c = (x+220)² + 145200,
b=220,
c= 145200
So,
c/b = 145200/220 = 660
c/b = 660/1 (if you need it in a fraction form) or 660.
Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
