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blagie [28]
3 years ago
11

Given the linear equation below, create a table of values to obtain ordered pairs.  Plot these ordered pairs to create a linear

graph.  Based on the graph you created, find three more solutions to the equation.
y= 3/4 × -6
​
Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

<u>Table</u>

<u />\left[\begin{array}{cc}x&y\\0&-6\\4&-3\\8&0\end{array}\right]

<u>Graph</u>

See attachment

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WILL GIVE BRAINLIEST. To who ever believes this.
Stella [2.4K]

Answer:lol

Step-by-step explanation:

Lol i do math stands for

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5 0
4 years ago
Read 2 more answers
4. Al restar 5 x ᶺ 2 – 8 x + 9 con – 9 + 16 x – 25 x ᶺ 2 se obtiene como resultado (Procedimiento)
Ierofanga [76]

Step-by-step explanation:

SE RESTAN ENTRE LOS NÚMEROS QUE TIENEN LA MISMA VARIAVLE.

(5x^{2} + 25x^{2}) - (8x - 16x) + (9 + 9) = 30x^{2} - 24x + 18

4 0
3 years ago
A baseball player hit 6060 home runs in a season. Of the 6060 home​ runs, 1919 went to right​ field, 2020 went to right center​
m_a_m_a [10]

Answer: (a) 0.317

               (b) 0.167

                (c) Not unusual

Step-by-step explanation:

Probability is defined as the chance of an event occurring.

Let S be a sample space and A be an event in the sample space, the probability of event A occurring can be found using the following:

P(A) = n(A) divided by n(S) where n(A) = number of elements in event A and n(S) = number of elements in the sample space.

(a) P(Right field) = Number of hits to the right field divided by total number of hits

                          = 1919/6060

                          =  19/60  which is approximately equal to 0.317

(b) P(Left field) = 1010/6060

                         = 1/6 which is approximately equal to 0.167

(c)  The probability that the home run was hit to the left field is 0.167.

    The probability of an unusual event is 0, therefore, it is possibly for the

    player to hit a home run to the left.        

8 0
3 years ago
Use logarithmic properties and the fact that ln(2) ≈ 0.69 and ln(3) ≈ 1.10 to approximate the value of each of the following log
bija089 [108]

Answer:

ln6 = 1.79

Step-by-step explanation:

The logarithm here has base e so it is a natural logarithm.

log_ex=lnx

lnx=y\\\Rightarrow e^y=x

According to the product rule of logarithms

ln(a\times b)=ln(a)+ln(b)

6=3\times 2

ln6=ln(3\times 2)\\\Rightarrow ln6=ln3+ln2\\\Rightarrow ln6=1.10+0.69\\\Rightarrow ln6=1.79

∴ ln6 = 1.79

3 0
4 years ago
2(b+3c) equivalent expressions<br>Options: <br><br>3(b+2c)<br>(b+3c) +(b+3c)<br>None of the above
Lana71 [14]
2(b + 3c) → We first need to simplify this.

Simplify.

2b + 6c

1st Option : 

3(b + 2c)

Simplify.

3b + 6c

This is INCORRECT, as it is not equal to 2b + 6c.

2nd Option :

(b + 3c) + (b + 3c)

Simplify.

2b + 6c

This is CORRECT because 2b+6c = 2b+6c

(b + 3c) + (b + 3c)  → Answer

~Hope I helped!~



5 0
3 years ago
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