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Bezzdna [24]
3 years ago
11

Multiply. Check picture.

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

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Given negative four and one sixth times negative three and fifteen hundredths, determine the product.
Contact [7]

The sum of the digits, B. thirteen and one eighth, is the product of the numerals.

<h3>How do you compute the value of the product?</h3>

According to the data, we are in the negative four hundred and one-sixth times the negative three hundred and fifteen-hundredths range.

This is going to be the product:

= (-4 1/6) × (-3 15/)

= - 4 1/6 × 3 3/20

= - 25/6 × -63/20

x= 13 1/8

In conclusion, The answer that you should choose is an option (d), which is thirteen and one-eighth.

Find out more about the product by visiting:

brainly.com/question/10873737

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3 0
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Answer: C (110)

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How do you solve this problem? What is a rewritten form of the radical(-8/726) It is supposed to be a squar root sign instead of
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I think the answer is negative 8 square root 726

then the answer if I am right sorry if I am not would be negative 88 square root 6

again sorry if wrong
5 0
3 years ago
If 3 * 9 + 2y = 47 what is the value of y
docker41 [41]
Answer: 10

Why?
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Hope this helps :D
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