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vazorg [7]
3 years ago
15

The minimum wage in 2003 was $5.15 this was W more than the minimum wage in 1996 write an expression for the minimum wage in 199

6
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
<span>The minimum wage in 2003 was $5. Let denote this minimum wage with: W_min_2003.
In 1996 the minimum wage was 15 the W_min_2003 ,so we can write:
W_min_1996=15*W_min_2003=15*5 USD= 75 USD.
The minimum wage in 1996 was 75 USD.</span>
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Answer:

$2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

Step-by-step explanation:

Let a, b, and c be the fractions of the $12,000 that is invested in the savings, bond, & money fund respectively.

Let S1, S2, S3 be the total monies from the savings, bond, & money fund after the year with interest respectively.

We know that a+b+c=1

and

S1+S2+S3 = 12000 + 860

S1+S2+S3 = 12860

From, the question, we know that b = 2a, and c = 1 - 3a based on the condition of 2 times more in the bond account that the savings account.

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S1+S2+S3 = 12860

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a = 220/1320

a = 0.1667

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S1 = 12480a = 12480 x 0.1667 ≈ $2080

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S3 = 13080 - 39240(0.1667) ≈ 6539

So, $2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

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