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vazorg [7]
3 years ago
15

The minimum wage in 2003 was $5.15 this was W more than the minimum wage in 1996 write an expression for the minimum wage in 199

6
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
<span>The minimum wage in 2003 was $5. Let denote this minimum wage with: W_min_2003.
In 1996 the minimum wage was 15 the W_min_2003 ,so we can write:
W_min_1996=15*W_min_2003=15*5 USD= 75 USD.
The minimum wage in 1996 was 75 USD.</span>
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line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equat
VMariaS [17]
Slope of the line J
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5 / 3

so
m = 5/3

If this line passes through (15,-1)
y = mx + c
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-1 = 25 + c
c = -26

equation is
y = (5/3)x - 26
7 0
3 years ago
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astra-53 [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
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Answer:

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Step-by-step explanation:

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to check your answer:

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3 0
2 years ago
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LuckyWell [14K]

Answer:

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Step-by-step explanation:

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7 0
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Vikki [24]

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8 0
3 years ago
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