Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
The value of the length DF is 17
<h3>How to determine the length DF?</h3>
The statement Triangle ABC = Triangle ADF means that the triangles ABC and ADF are congruent triangles.
So, we have:
AB = AD
AC = A F
BC = DF
Given that BC = 17;
The equation BC = DF becomes
17 = DF
Rewrite as:
DF = 17
Hence, the value of the length DF is 17
Read more about congruent triangles at:
brainly.com/question/1675117
#SPJ1
Answer:
(-2.5, 2)
Step-by-step explanation:
just find where the points meet up lol
Answer:
16
Step-by-step explanation:
A) x * y = 42 (or x = 42/y)
B) x + y = 23
B) 42/y + y = 23
42 + y^2 = 23y
y^2 -23y + 42 = 0
The numbers are 21 and 2
