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4 years ago

How can you tell that a function is linear or nonlinear

1 answer:

6 0

In this lesson, you learned about linear and nonlinear functions. The equation of a linear function has no exponents higher than 1, and the graph of a linear function is a straight line. The equation of a nonlinear function has at least one exponent higher than 1, and the graph of a nonlinear function is a curved line. hope that helped

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What is a solution to (x-2)(x+10)=13? a: x=3 b: x=8 c: x=10 d: x=11

pishuonlain [190]

(x-2)(x+10)=13

x^2 + 10x - 2x - 20 = 13

x^2 + 8x - 20 - 13 = 0

x ^2 + 8x - 33 = 0

(x + 11) (x - 3) = 0

x + 11 = 0

x = -11

x - 3 = 0

x = 3

The answer is clearly x = 3.

Choice a.

5 0

4 years ago

Read 2 more answers

Find m<YQR pls need grade gud.

DaniilM [7]

Answer:

21°

Step-by-step explanation:

We can prove these two triangles congruent by the HL (Hypotenuse-Leg) theorem. Then, we know that m<YQR is congruent to m<PQY. We can then use their given values to form an equation.

5x+6=16x-27

Continue to solve . . .

33 = 11x

x=3

Therefore, we can plug this value of 3 into the expression for the value of m<YQR, and you will get

(16 x 3) - 27, which is equal to 21°.

4 0

3 years ago

The area of a circle is 28.26 square feet. What is the circle's circumference?

Marina86 [1]

Reverse the formula of pi x r^2 = area to find r, the radius.
Then, use r in the formula 2pi x r to calculate the circumference.

4 0

3 years ago

17. Stratus long distance charges $2.45 for the first three minutes of a call then

Bess [88]

$4.27
You subtract 17-3 = 14
Then multiple 14 by 0.13
Then add it by 2.45
Giving you 4.27

5 0

3 years ago

HELP ME PLS

kolbaska11 [484]

Answer:

Slope = 27/11

AB = 29.15 u

Step-by-step explanation:

Given :-

Two points are given to us .
The points are A(7,15) and B(18,42)

To Find :-

The slope of the line .
The length of line AB .

We can find the slope of the line passing through the points $( x_1,y_1)$ and $( x_2,y_2)$ as ,

$\implies m = \dfrac{ y_2-y_1}{x_2-x_{1}}$

Plug in the respective values ,

$\implies m = \dfrac{ 42-15}{18-7} \\\\\implies \boxed{ m = \dfrac{ 27}{11 }}$

Hence the slope of the line is 27/11 .

$\rule{200}2$

Finding the length of AB :-

We can find the distance between them by using the Distance Formula .

$\implies Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2} \\\\\implies Distance =\sqrt{ (18-7)^2+(42-15)^2 } \\\\\implies Distance =\sqrt{ 11^2 + 27^2 } \\\\\implies Distance =\sqrt{ 121 + 729 } \\\\\implies Distance = \sqrt{ 850} \\\\\implies \boxed{ Distance = 29.15 \ units }$

Hence the length of AB is 29.15 units .

5 0

3 years ago