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vivado [14]
2 years ago
7

Jeremy raised $250 for charity last year. This year he raised 20% more than he raised last year. How much money did Jeremy raise

this year?
Mathematics
2 answers:
Lesechka [4]2 years ago
5 0
You would find this by doing 250 times 20% which is .2 and you would get 50 so you would add 250 plus 50 and get 300.
The answer is $300
RSB [31]2 years ago
3 0

Answer: $300

Step-by-step explanation: Multiply 250*0.2 = 50.

50 is how much more jeremy earned. so 250+50= 300.

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Eduardo rented a bike from James' Bikes. It cost $19 plus $6 per hour. If Eduardo paid $49 then he rented the bike for how many
solniwko [45]
So to solve this, you would have to write the equation, which is 49=6x+19

Then solve your equation.

49=6x+19
-19        -19
30=6x
/6     /6

5=x

So he rented it for 5 hours.

8 0
2 years ago
Which function, g or h, is the inverse function for function ƒ? the function h because the graphs of ƒ and h are symmetrical abo
xz_007 [3.2K]
A function and it's inverse function, when graphed, will be symmetrical across the line y=x. 
Without seeing your graphs, I can't tell you if it's g or h. Look for the function which mirrors 'f' across y=x, which is a diagonal line passing through the origin (0,0) of the graph. 
4 0
3 years ago
If Cp = Rs 660, Loss percent = 5% find Sp​
Aneli [31]

Answer:

SP = 627 Rs

Step-by-step explanation:

Percentage loss is calculated as

\frac{CP-SP}{CP} , then

\frac{660-SP}{660} = 5% = 0.05 ( multiply both sides by 660 )

660 - SP = 33 ( subtract 660 from both sides )

- SP = - 627 ( multiply both sides by - 1 )

SP = 627 Rs

8 0
2 years ago
30<br> find the length of AB.<br> D 20 C<br> Show your work
vovikov84 [41]
You use Pythagoras theorem for this:
You add 52 and 20 for AC which is 72
So you do
X^2 = 72^2 + 30^2
X^2 =5184 + 900
X^2= 6084
X = 6084 squared root
X= 78
4 0
2 years ago
What is the minimum value of the objective function, C with given constraints? C=5x+3y {⎨x+3y≤9 {5x+2y≤20 {x≥1 {y≥2
Solnce55 [7]

Answer:

The answer is below

Step-by-step explanation:

Plotting the following constraints using the online geogebra graphing tool:

x + 3y ≤ 9         (1)

5x + 2y ≤ 20    (2)

x≥1 and y≥2      (3)

From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).

We need to minimize the objective function C = 5x + 3y. Therefore:

At point A(1, 2): C = 5(1) + 3(2) = 11

At point B(1, 2.67): C = 5(1) + 3(2.67) = 13

At point C(3, 2): C = 5(3) + 3(2) = 21

Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.

3 0
3 years ago
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