Remember
(x^m)/(x^n)=x^(m-n)
(q^(33/4))/(q^8)=q^((33/4)-8)
what is 33/4-8?
33/4-8=33/4-32/4=1/4
result is
q^1/4 or
![\sqrt[4]{q}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Bq%7D%20)
answer is
Answer:
Step-by-step explanation:
A quadratic function has the formula ax² + bx + c
- To determine if a graph will be narrow or wide, the leading coefficient, a, will be the factor that determines this
- The greater the coefficient, the narrower the parabola
- The lesser the coefficient, the wider the parabola
Here all of the functions are in the form ax²
- In
, our "a" term is 
- In y = -2x², our "a" term is -2
- In y = -3x², our "a" term is -3
- In
, our "a" term is 
We can eliminate the two functions with the negative coefficients because they are much smaller than the two functions with the fractions as coefficients, and will therefore open much wider.
We can now compare the two remaining functions, and 
- Giving the two fractions common denominators would turn them into
and 
- The equation with the larger fraction will be the parabola that is the narrowest. In this case, it is the .
- Therefore, will have the narrowest graph
A + 5x + 2 means . . .
a can be any number
5 is multipled by x
x can be any number
2 stays the same
So it would be . . .
a + 5x + 2
An example of this is a would be 6 and x would be 2 so it would be written as . . .
6 + 5(2) + 2 = 18.
Hope this helps
And have a NICE DAY .... :) :D
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