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Illusion [34]
3 years ago
15

The manager of a public pool is counting the people who came to swim in June and July. There were 600 people who came in June. T

here were 800 people who came in July. What is the percent increase in people who came from June to July?
25%


200%


3313%


75%
Mathematics
2 answers:
Serjik [45]3 years ago
8 0
So,

The percent increase is basically the same as percent decrease except that you subtract the June count from the July count.  If you let x be the June count and y be the July count, you can write it mathematically as follows:
\frac{y -x}{x}  = percent\ increase

Substitute.
\frac{800 - 600}{600} = percent\ increase
\frac{200}{600} \ or\  \frac{1}{3} = percent\ increase

The percent increase in people from June to July is 33.3333333%, which is not one of the options you put there.
GarryVolchara [31]3 years ago
7 0

Answer: 33 1/3

Step-by-step explanation:

For ttm i know it's right

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GenaCL600 [577]

Answer:

<h2>-25b + 101</h2>

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-8(2b-7)-9(b-5)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(-8)(2b)+(-8)(-7)+(-9)(b)+(-9)(-5)\\\\=-16b+56-9b+45\qquad\text{combine like terms}\\\\=(-16b-9b)+(56+45)\\\\=-25b+101

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Pls help I'll give brainliest!
natali 33 [55]

Answer:

95

Step-by-step explanation:

t_n =  {n}^{2}  - 5 \\  \therefore \: t_{10} =  {10}^{2}  - 5 \\ \therefore \: t_{10} = 100  - 5 \\ \huge \red{ \boxed{\therefore \: t_{10} = 95 }}\\

10th term of the sequence is 95.

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