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posledela
3 years ago
15

Can someone please help

Mathematics
1 answer:
Bas_tet [7]3 years ago
7 0
Number 6 is C, Number 7 is A. Do you need number 8? if so I will edit answer and add pic
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Area of the Shaded Region rectangle within reactanlge
Alik [6]

Answer:

132

Step-by-step explanation:

First you need to find the area of both regions (shaded and not shaded)

To find the shaded regions area multiply length by width

20 x 8 = 160

Then find the area of the unshaded region

7 x 4 = 28

Finally subtract the unshaded region from the shaded region

160 - 28 = 132

7 0
3 years ago
ok so if Tony logs-in 10 hours of gaming a day and his gf Shara says if he doesn't get a job she will leave him for Dave.. now h
puteri [66]

Answer:

10 hours

Step-by-step explanation:

shara takes L

5 0
2 years ago
there were 2,683 books sold at a bookstore this year. there were 1,317 more books sold last year. how many books were sold last
Nadya [2.5K]

Answer:

4,000

Step-by-step explanation:

you take this years total (2683)

and add how many more there was last year (1317)

then you get 4000!!

hope it helps

4 0
3 years ago
Write an equation of the circle graphed below
dezoksy [38]

Answer:

(-1,1)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the perimeter of △ABC?
timofeeve [1]
<h3>Given</h3>
  • ΔABC
  • A(-3, -1), B(0, 3), C(1, 2)
<h3>Find</h3>
  • the length of the perimeter of ΔABC to the nearest tenth
<h3>Solution</h3>

The perimeter of a triangle is the sum of the lengths of its sides. The length of each side can be found using the Pythagorean theorem. Effectively, each pair of points is treated as the end-points of the hypotenuse of a right triangle with legs parallel to the x- and y-axes. The leg lengths are the differences betweeen the x- and y- coordinates of the points.

The difference of the x-coordinates of segment AB are 0-(-3) = 3. The y-coordinate difference is 3-(-1) = 4. So, the leg lengths of the right triangle whose hypotenuse is segment AB are 3 and 4. The Pythagorean theorem tells us

... AB² = 3² +4² = 9 +16 = 25

... AB = √25 = 5

You may recognize this as the 3-4-5 triangle often introduced as one of the first ones you play with when you learn the Pythagorean theorem.

LIkewise, segment AC has coordinate differences of ...

... C - A = (1, 2) -(-3, -1) = (4, 3)

These are the same leg lengths (in the other order) as for segment AB, so its length is also 5.

Segment BC has coordinate differences ...

... C - B = (1, 2) -(0, 3) = (1, -1)

The length of the line segment is figured as the root of the sum of squares, even though one of the coordinate differences is negative. The leg lengths of the right triangle used for finding the length of BC are the absolute value of these differences, or 1 and 1. Then the length BC is

... BC = √(1² +1²) = √2 ≈ 1.4

So the perimeter of the triangle ABC is

... AB + BC + AC = 5 + 1.4 + 5 = 11.4 . . . . perimeter of ∆ABC in units

_____

Please be aware that the advice to "round each step" is <em>bad advice,</em> in general. For real-world math problems, you only round the final result. You always carry at least enough precision in the numbers to ensure that there will not be any error in the final rounding.

In this problem, the only number that is not an integer is √2, so it doesn't really matter.

7 0
3 years ago
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