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suter [353]
3 years ago
13

If 2^5/2^a= 2^2, then a=

Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer: 3

Step-by-step explanation:

\frac{2^5}{2^a}=2^2

Multiply by 2^a

2^a*\frac{2^5}{2^a}=2^2*2^a

2^5=2^2*2^a

Divide by 2^2 to isolate 2^a

\frac{2^5}{2^2}=\frac{2^2*2^a}{2^2}

2^3=2^a

Since we have the same base (2), we equal their exponents.

3=a

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2 years ago
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Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
This number is in scientific notation. 2. 4 × 10-4 Convert the number into standard notation. What is the value? 2. 4 × 10-4 =.
dusya [7]

The value of the number 2.4x10⁻⁴ in the standard notation is 0.00024.

<h3>What are Scientific notations?</h3>

The way through which a very small or a very large number can be written in shorthand. In scientific notations when a number between 1 and 10s is multiplied by a power of 10.

For example, 6,500,000,000,000 can be written as 6.5×10¹².

As the value of the scientific notation is given 2.4x10⁻⁴, therefore, for bringing it in the standard form we need to shift the decimal to the left by four digits. So,

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Hence, the value of the number 2.4x10⁻⁴ in the standard notation is 0.00024.

Learn more about Scientific notation:

brainly.com/question/1740231

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Answer:

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Step-by-step explanation:

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Rectangle

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