24√3^4 i hope this helps if its wrong, im sorry.
Answer:
c
Step-by-step explanation:
Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

The odd multiples of 9,
, in the range
form the set

Each member of the set is a term of the arithmetic progression

where the values of
range from 0 to 4, or 
Putting these facts together, we get the result

Learn more about set-builder notation here: brainly.com/question/17238769
X6 – 9x3 + 8 = 0
let u = x^3
u^2 - 9u + 8 = 0
(u-8)(u-1) = 0
u = 1,8
back substitute
1 = x^3
8 = x^3
<span>x = 1 , 2</span>