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postnew [5]
4 years ago
13

You are in a locked room with only one way to escape--you must open the door with the correct line plot as the key. Your only cl

ues lie in the data that was provided for you: Red Jewel 5, Blue Jewel 4, White Jewel 6, Green Jewel 5. What would a correct line plot look like?
Mathematics
1 answer:
KengaRu [80]4 years ago
7 0

Answer:

A line plot consists on a line with N separated marks, where each position may represent an event. And over those positions, you put crosses that represent each time that the given event happened.

For example, here we have:

Red 5

Blue 4

White 6

Green 5

So we can make a line plot that in the bottom (in the horizontal line) we have 4 marks, one for each color.

on top of the red mark, we have 5 crosses,

on top of the blue mark, we have 4 crosses

on top of the white mark we have 6 crosses

on top of the green mark we have 5 crosses.

And it is useful to put it in order, so the color with fewer marks goes first and so on.

Then the order of the colors in the line plot is:

Blue, red, green, white.

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2<br> What is the period of f(x) = sin(x)?<br> €<br> O<br> 2<br> O 20
Ad libitum [116K]

Answer:

Period: 2\pi

Step-by-step explanation:

The function f(x)=asin(bx-c)+d has a period of \frac{2\pi}{|b|}, therefore f(x)=sinx has a period of 2\pi, where the wave cycle of the function repeats every 2\pi units. See the attached graph for a visual.

8 0
3 years ago
Complete he statement below. Then use a number line to find the sum 5 + ( -4 )
skad [1K]

Answer:

The statement is 6 in the negative direction

5 + (-4) = 1

Step-by-step explanation:

7 0
3 years ago
HELP! COME TO THIS QUESTION!!!!
marissa [1.9K]

Answer:

1: False.

2: False.

3: True.

4: False.

5: False.

6: False.

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Hope this helps!

8 0
3 years ago
Choose a number between 67 and 113 that is a multiple of 3, 9, and 12
Anestetic [448]
72 is multiples of 3,9, and 12
3 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
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