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postnew [5]
3 years ago
13

You are in a locked room with only one way to escape--you must open the door with the correct line plot as the key. Your only cl

ues lie in the data that was provided for you: Red Jewel 5, Blue Jewel 4, White Jewel 6, Green Jewel 5. What would a correct line plot look like?
Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Answer:

A line plot consists on a line with N separated marks, where each position may represent an event. And over those positions, you put crosses that represent each time that the given event happened.

For example, here we have:

Red 5

Blue 4

White 6

Green 5

So we can make a line plot that in the bottom (in the horizontal line) we have 4 marks, one for each color.

on top of the red mark, we have 5 crosses,

on top of the blue mark, we have 4 crosses

on top of the white mark we have 6 crosses

on top of the green mark we have 5 crosses.

And it is useful to put it in order, so the color with fewer marks goes first and so on.

Then the order of the colors in the line plot is:

Blue, red, green, white.

You might be interested in
Which of these triangle pairs can be mapped to each other using a translation and a rotation about point A?
Vladimir79 [104]

Answer:

<u>Figure A</u>

Step-by-step explanation:

See the attached figure which represents the given options

We are to select the correct pair of triangles that can be mapped to each other using a translation and a rotation about point A.

As shown: point A will map to point L, point R will map to point P and point Q will map to point K.

we will check the options:

<u>Figure A</u>: the triangle ARQ and LPK can be mapped to each other using a translation and a rotation about point A.

<u>Figure B: </u> the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line RA.

<u>Figure C:</u> the triangle ARQ and LPK can be mapped to each other using a translation and a reflection about the line QA.

<u>Figure D:</u> the triangle ARQ and LPK can be mapped to each other using a rotation about point A.

So, the answer is figure A

<u>The triangle pairs of figure A can be mapped to each other using a translation and a rotation about point A.</u>

3 0
3 years ago
Read 2 more answers
Help i need help i can't figure this out​
EastWind [94]

Answer: A) 23

Step-by-step explanation:

3^2 + ( 6 - 2 ) ⋅ 4 -6/3

3^2 + 4 ⋅ 4 -6/3

9 + 4 ⋅ 4 -6/3

9 + 16 -6/3

25 - 6/3

75/3 -6/3 = 69/3

69/3 = 23

7 0
3 years ago
Read 2 more answers
Even though the elimination method is easy I still have trouble with it
kicyunya [14]

Answer:

(1,2)

Step-by-step explanation:

x+4y = 9

2x -4y= -6

Add the equations together

x+4y = 9

2x -4y= -6

-------------------

3x +0y = 3

3x=3

Divide by 3

3x/3 = 3/3

x=1

Now find y

x+4y = 9

1 +4y =9

Subtract 1 from each side

4y = 8

Divide by 4

4y/4 = 8/4

y =2

6 0
3 years ago
Find angle D if angle B = 50
Mariana [72]
<h3>Answer:  80 degrees</h3>

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

  • angle A = 90
  • angle E = 100
  • angle C = 90
  • angle D = unknown

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

5 0
3 years ago
15 points! Thank you
Pepsi [2]

10x^2+27x-28=10x^2+35x-8x-28=5x(2x+7)-4(2x+7)\\\\=(2x+7)(5x-4)\\\\Answer:\ D.\ 2x+7

5 0
2 years ago
Read 2 more answers
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