Answer:
Step-by-step explanation:
for the first one is
Domain:
(−∞,∞),{x|x∈R}
Range:
(−7,∞),{y|y>−7}
Horizontal Asymptote:
y=−7
y-intercept(s):
(0,−6)
the second one is
y-intercept(s):
(0,8)
Horizontal Asymptote:
y=2
Domain:
(−∞,∞),{x|x∈R}
Range:
(2,∞),{y|y>2}
Answer:the size of the button hole is 2.35 cm
Step-by-step explanation:
For a button to fit through its button-hole, the hole needs to be the size of the buttons diameter.
The formula for determining the circumference of a circle is expressed as
Circumference = πd or 2πr
Where
d represents the diameter of the circle
π is a constant given as 3.14
From the information given, the circumference of the button is 7.38 cm. Therefore, the diameter of the button will be
d = circumference/π = 7.38/3.14
d = 2.35 cm
The correct answer is 3.53
Answer:
StartRoot 2 squared + 6 squared EndRoot
Step-by-step explanation:
we have
A(4,3) and B(-2,1)
we know that
the formula to calculate the distance between two points is equal to

substitute the given values



therefore
StartRoot 2 squared + 6 squared EndRoot
Answer:
-----×1/72
Step-by-step explanation:
The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.
If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...
(-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8
_____
Here, we're going to evaluate what you have written according to the usual rules as described above.
(-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9
= -----×1/8/9
= -----×1/72
_____
<em>Comment on the arithmetic</em>
Fractions are multiplied and divided in the usual way:
a/b×c = (a×c)/b
a/b/c = (a/b) × (1/c) = a/(b×c)
___
<em>Comment on fractions and parentheses</em>
Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)