Answer: 35
Step-by-step explanation:
Given : A bag contains four red marbles, two green ones, one lavender one, three yellows, and one orange marble.
Total = 4+2+1+3+1=11
To find sets of four marbles include none of the red ones, we need to exclude red marbles when we count the total number of marbles.
Then, the total marbles(exclude red) =11-4=7
Now, the combination of 7 marbles taking 4 at a time is given by :-
Hence, the number of sets of four marbles include none of the red ones = 35
The <em>correct answers</em> are:
It would take 5 months and she would save $250.
Explanation:
Let m be the number of months.
For the first way of saving, $200 up front and $10 each month, the expression would be
200+10m.
For the second way of saving, $100 up front and $30 each month, the expression would be
100+30m.
Setting them equal gives us the equation
200+10m = 100+30m
Subtract 10m from each side:
200+10m-10m = 100+30m-10m
200 = 100+20m
Subtract 100 from each side:
200-100 = 100+20m-100
100 = 20m
Divide both sides by 20:
100/20 = 20m/20
5 = m
It would take 5 months.
$200 up front and $10 each month for 5 months:
200+10m
200+10(5)
200+50
250
She would save $250.
Answer:
Option (1) is the correct option.
Step-by-step explanation:
Function 1,
f(x) = 4x² + 8x + 1
= 4(x² + 2x) + 1
= 4(x² + 2x + 1 - 1) + 1
= 4(x² + 2x + 1) - 4 + 1
f(x) = 4(x + 1)² - 3
This graph opens up with the vertex or minimum point at (-1, -3)
So, the minimum value of the function is (-3) at x = -1.
Function (2)
From the given table minimum value of the function is 0 at x = -1 or minimum point as (-1, 0)
Therefore, Function 1 has the least minimum value and its coordinates are (-1, -3)
Option (1) is the correct option.
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option
I am pretty sure number 3 is the right answer
