
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
7(x-10)
Step-by-step explanation:
7×(x-10)
you ×7by whatever x-10 is
121 x 12 = 1452 so over 1500 is not a correct estimate. Less than 1500 is the right estimate
Answer:
A:
C -20 -15 -5
F(C) -4 5 23
Step-by-step explanation: