Answer:
- movie: $1.25
- video game: $5.25
Step-by-step explanation:
Let m and v represent the rental costs of movies and video games, respectively. The two rentals can be described by the equations ...
5m +3v = 22
2m +6v = 34
We notice that the coefficient of v in the second equation is 2 times that in the first equation. This will make it easy to eliminate v as a variable.
Subtracting the second equation from 2 times the first gives ...
2(5m +3v) -(2m +6v) = 2(22) -(34)
8m = 10 . . . . . . . . . . . simplify
m = 10/8 = 1.25 . . . . . divide by the coefficient of m
Using this in the second equation, we can find v:
2(1.25) +6v = 34 . . . . .substitute for m
6v = 31.50 . . . . . . . . . subtract 2.50
v = 5.25 . . . . . . . . . . . divide by the coefficient of v
The rental cost for a movie is $1.25; for a video game it is $5.25.
Answer:
<h3>
$ ![\underline{ \underline { \sf{ \bold{66.67}}}}](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Cunderline%20%7B%20%5Csf%7B%20%5Cbold%7B66.67%7D%7D%7D%7D)
</h3>
Step-by-step explanation:
Price of stock bought = $ 59
% rise = 13%
Price of stock rise :
⇒![\sf{13\% \: of \: 59}](https://tex.z-dn.net/?f=%20%5Csf%7B13%5C%25%20%5C%3A%20of%20%5C%3A%2059%7D)
⇒![\sf{ \frac{13}{100} \times 59}](https://tex.z-dn.net/?f=%20%5Csf%7B%20%5Cfrac%7B13%7D%7B100%7D%20%20%5Ctimes%2059%7D)
⇒$ ![\sf{7.67}](https://tex.z-dn.net/?f=%20%5Csf%7B7.67%7D)
New price is 13% more than $ 59
Hence, New price = $ 57 + $ 7.67
= $ 66.67
Hope I helped!
Best regards!!
Answer:
hi lol I need to type 20 characters
Answer:
The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is 0.10
Step-by-step explanation:
The Uniform Distribution, also known as Rectangular Distribution, is a type of Continuous Probability Distribution. It has a continuous random variable restricted to a finite interval and its probability function has a constant density during this interval.
The formula of probability if given by:
f(x)=
![\left \{ {{\frac{1}{b-a}; \ a \leq x \leq b } \atop {0}; \ x \ otherwise } \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B%5Cfrac%7B1%7D%7Bb-a%7D%3B%20%5C%20a%20%5Cleq%20x%20%5Cleq%20b%20%20%7D%20%5Catop%20%7B0%7D%3B%20%5C%20x%20%5C%20otherwise%20%7D%20%5Cright.)
In this exercise a= 46.0 and b= 56.0
The probability of selecting a class that runs between 50.2550.25 and 51.2551.25 minutes is:
![\int\limits^{51.25}_{50.25} {\frac{1}{56-46} } \, dx = \int\limits^{51.25}_{50.25} {\frac{1}{10} } \, dx = \frac{1}{10} \times (51.25 - 50.25)=\frac{1}{10}=0.1](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B51.25%7D_%7B50.25%7D%20%7B%5Cfrac%7B1%7D%7B56-46%7D%20%7D%20%5C%2C%20dx%20%3D%20%5Cint%5Climits%5E%7B51.25%7D_%7B50.25%7D%20%7B%5Cfrac%7B1%7D%7B10%7D%20%7D%20%5C%2C%20dx%20%3D%20%5Cfrac%7B1%7D%7B10%7D%20%5Ctimes%20%2851.25%20-%2050.25%29%3D%5Cfrac%7B1%7D%7B10%7D%3D0.1)
You plug them is them solve 6(13) then 6 *13 answer sould be 78