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3 years ago

Which one is better ketchup or mustard

Mathematics

1 answer:

iris [78.8K]3 years ago

5 0

Ketchup lol mustard just nasty 9

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Write an expression equivalent to h^6/h^3 in the form of h^m

Pavel [41]

Answer:

$h^3 = h^m$

Step-by-step explanation:

$\frac{h^6}{h^3} = h^m$

6 - 3 = 3

keep the base same, therefore

$h^3 = h^m$

Hope this helps!

3 0

3 years ago

What does range mean in maths

Karo-lina-s [1.5K]

The range is the difference between the highest and lowest values in a set of numbers. To find it, subtract the lowest number in the distribution from the highest.

4 0

3 years ago

Read 2 more answers

2. Four friends share 3 apples equally.

Slav-nsk [51]

Answer:

1/3

Step-by-step explanation:

Each friend gets 1/3 of an apple

5 0

3 years ago

PLS HELP! I NEED TO FIND THE SURFACE AREA OF THIS CYLINDER!

Contact [7]

Exact Surface Area = 378pi

Approximate Surface Area = 1186.92

The approximate surface area uses pi = 3.14

The units are cm^2 or "square cm".

=========================================================

Work Shown:

SA = surface area of cylinder

SA = 2*pi*r^2 + 2*pi*r*h

SA = 2*pi*7^2 + 2*pi*7*20

SA = 2*pi*49 + 2*pi*140

SA = 2*49*pi + 2*140*pi

SA = 98pi + 280pi

SA = 378pi ..... exact surface area

SA = 378*3.14

SA = 1186.92 ..... approximate surface area

----------

Side note: The diameter 14 cuts in half to get the radius r = 7

3 0

3 years ago

Read 2 more answers

What is the solution of √x-5 = x-11

PIT_PIT [208]

Hey!

To solve x in this equation we must first add five to both sides to get $\sqrt{x}$ on its own.

Original Equation :
$\sqrt{x} - 5 = x - 11$

New Equation {Added 5 to Both Sides} :
$\sqrt{x} =x-6$

Now we must square both sides of the equation.

Old Equation :
$\sqrt{x} =x-6$

New Equation {Changed by Squaring Both Sides} :
$x= x^{2} -12x+36$

And now we must solve the new equation.

Step 1 - Switch sides
$x^{2} -12x+36=x$

Step 2 - Subtract x from both sides
$x^{2} -12x+36-x=x-x$

Step 3 - Simplify
$x^{2} -13x+36=0$

Now we need to solve the rest of the equation using the quadratic formula.

$\frac{-(-13)+ \sqrt{(-13) ^{2}-4*1*36 } }{2*1}$

${13+ \sqrt{(-13)^{2}-4*1*36 }=13+ \sqrt{25}$

$\frac{13+ \sqrt{25}}{2}$

$\sqrt{25}=5$

$\frac{13+5}{2}$

$\frac{18}{2}$

9

$\frac{-(-13)- \sqrt{(-13) ^{2} -4*1*36} }{2*1}$

4

So, this means that in the equation $\sqrt{x} -5=x-11$ , x = 9 and x = 4.

Hope this helps!

- Lindsey Frazier ♥

4 0

3 years ago