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jonny [76]
3 years ago
10

Which one is better ketchup or mustard

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
Ketchup lol mustard just nasty 9
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Factor 4a^2-25. Please
Dmitrij [34]

Answer:

(2 a - 5) (2 a + 5)

Step-by-step explanation:

Factor the following:

4 a^2 - 25

4 a^2 - 25 = (2 a)^2 - 5^2:

(2 a)^2 - 5^2

Factor the difference of two squares. (2 a)^2 - 5^2 = (2 a - 5) (2 a + 5):

Answer: (2 a - 5) (2 a + 5)

8 0
3 years ago
How to find the x and y intercepts for linear equations
balandron [24]

Answer:

plug in 0 for y and solve for x  

to find y plug in 0 for x

Step-by-step explanation:

6 0
3 years ago
Q#33: Tell whether the lines for the pair of the equation are parallel, perpendicular, or neither?
Rashid [163]

Answer:

i think its neither

Step-by-step explanation:


5 0
3 years ago
Point M is the midpoint of PQ. The coordinates of P and M are given below.
Zepler [3.9K]

The coordinates of Q are (-1,6)

Further Explanation:

Given points are:

(x_m, y_m) = (5, -2)\\(x_p,y_p) = (11, -10)

The formula for mid-pint is:

(x_m, y_m) = (\frac{x_p+x_q}{2} , \frac{y_p+y_q}{2})\\From\ this\ we\ get\\x_m = \frac{x_p+x_q}{2}\\Putting\ values\\5 =\frac{11+x_q}{2}\\5*2 = 11+x_q\\10 = 11+x_q\\10-11 = x_q\\x_q = -1\\AND\\y_m = \frac{y_p+y_q}{2}\\-2 = \frac{-10+y_q}{2}\\-2*2 = -10+y_q\\-4 = -10+y_q\\-4+10 = y_q\\y_q = 6

The coordinates of Q are (-1,6)

Keywords: Coordinate geometry, mid-point

Learn more about mid-point at:

  • brainly.com/question/11018983
  • brainly.com/question/11175936

#LearnwithBrainly

7 0
3 years ago
The manager of The Cheesecake Factory in Boston reports that on six randomly selected weekdays, the number of customers served w
Oliga [24]

Answer:

(121.576 ; 273.424)

Step-by-step explanation:

Given the data:

175, 125, 180, 220, 240, 245

We can calculate the mean and standard deviation

Mean = Σx/ n = 1185 / 6 = 197.5

Standard deviation = 46.125 (calculator)

The confidence interval :

Mean ± margin of error

Margin of Error = Tcritical * s/sqrt(n)

Tcritical at 99%, df = n - 1 ; 6 - 1 = 5

Tcritical = 4.032

Margin of Error = 4.032 * 46.125/√6

Margin of error = 75.924

Confidence interval :

197.5 ± 75.924

Lower boundary = 197.5 - 75.924 = 121.576

Upper boundary = 197.5 + 75.924 = 273.424

(121.576 ; 273.424)

5 0
3 years ago
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