Answer:
<h2>A: -12</h2>
Step-by-step explanation:
Put the values of a = -46 and b = 34 to the expression a + b:
-46 + 34 <em>use the commutative property a + b = b + a</em>
= 34 + (-46) = 34 - 46 = -12
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
The question above makes use of the concept of ratio and proportion in a form of scaling. If we let x and y be the true length and width, the equations that best describe them are,
0.5 cm / 1 inch = 2.5 cm / x in ; x = 5 in
0.5 cm / 1 inch = 4.75 cm / y in ; y = 9.5 in
Therefore, the true length and width of Rueben's flag is 5 in and 9.5 in, respectively.
Answer:
The amount of money he owes when he begins making payments:
A = 13000 x ( 1 + rate/12)^month
= 13000 x (1 + (3.6/100)/12)^15
= 13597.45 dollar
Hope this helps!
:)
