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natima [27]
3 years ago
10

ΔCDE was translated down and right to form triangle

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0
Statements 1,2,4, and 5 are true
aliya0001 [1]3 years ago
6 0

Answer:

1, 2, 5, 6

.................

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The equation of line f is y = 1/4x -1. line g includes the point (1,-6) and is perpendicular to line f . What is the equation of
Gwar [14]
Y=-4x+b
-6=-4+b
-2=b
y=-4x-2
7 0
3 years ago
PLEASE HURRY<br> WILL GIVE BRAINLIEST
fiasKO [112]
The answer would be (8pi +12) in^2
This is because to solve for the semicircle the equation is:
1/2*pi*r^2 1/2*pi*16
And the equation for the triangle is:
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(Plz mark Brainliest have a nice day)
3 0
3 years ago
Find the magnitude of vector v that has an initial point of (1, 3) and a terminal point of (7, 1)
solmaris [256]

Answer:

It's totally correct with no doubt

3 0
3 years ago
Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu
dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\Substituting the values

d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\

So the total distance travelled is 1031 feet.

4 0
3 years ago
Joseph traveled from Boston to Framingham at 50 mph and then back to Boston
Solnce55 [7]

Answer:

44.44 mph

Step-by-step explanation:

7 0
2 years ago
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