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3 years ago

ΔCDE was translated down and right to form triangle

Mathematics

2 answers:

ASHA 777 [7]3 years ago

8 0

Statements 1,2,4, and 5 are true

aliya0001 [1]3 years ago

6 0

Answer:

1, 2, 5, 6

.................

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If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago

Make x the subject<br> 5y + 2x = 25

Tpy6a [65]

Answer:

x = -5/2 y +25/2

Step-by-step explanation:

5y + 2x = 25

Subtract 5y from each side

5y + 2x -5y= -5y+25

2x = -5y +25

Divide by 2

2x/2 = -5y/2 +25/2

x = -5/2 y +25/2

3 0

3 years ago

From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21

ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:

We are going to take 4 of the 5 even numbers in the box so we have

$5C4=5$

Case 2: When all 4 numbers are odd:

We are going to take 4 of the 5 odd numbers in the box, so we have

$5C4=5$

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

$5C2 * 5C2$

Remember that we obtain the probability from

$\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}$

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:

We are taking 4 of the 10 cards:

$10C_4=210$

Hence we have that the probability that their sum is even

$\frac{5+5+100}{210}=\frac{11}{21}$

8 0

3 years ago

A right triangle has legs of lengths 9 cm and 12 cm. calculate the length of the hypotenuse?

just olya [345]

Let the legs of the triangle be a and b, and the hypotenuse c.

Your first instinct might tell you to use the Pythagorean theorem to go about solving this because $c= \sqrt{a^{2}+b^{2}}$ . This works, but it is slow.

The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.

6 0

3 years ago

Read 2 more answers

If a liquid weighs 2 pounds and has capacity 3 gallons. What is its density

brilliants [131]

8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)

hope it helps

6 0

3 years ago

Read 2 more answers