Question

You select a card at random from the cards that make up the word replacement. On each card, there is one letter. Without replacing the card, you choose a second card. Find the probability of choosing a vowel and then not a vowel

Answer 1

In the word replacement, there are 11 letters.

4 of them are vowels : e, a, e, e

7 of them are not vowels : r, p, l, c, m, n, t

The probability of getting a vowel the first try is 4/11.

The probability of getting something that is not a vowel is 7/10. The denominator is one less because the vowel card is not replaced, meaning there is one less card to choose from.

Multiply.
4/11*7/10
=28/110
=14/55

The probability is 14/55.

Hope this helps!