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Nat2105 [25]
3 years ago
13

How many different intergers can have the same absolute value

Mathematics
2 answers:
Lerok [7]3 years ago
8 0
Only two integers can have the same distance from 0, so 2
morpeh [17]3 years ago
8 0
Only two. Take any integer x. The integer with the same absolute value is -x. -10 and 10 have the same magnitude or absolute value
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You are a real estate agent with ABC Real Estate company. You help sell a home for $155,000. The total commission is 6.5%. Your
gtnhenbr [62]

Answer:

$3,929.25.

Step-by-step explanation:

First, calculate the total commission.  That's found by multiplying the selling price ($155,000) by 0.065.  The result:  The total commission is $10,075.

Your company receives 60% of that.  So we multiply $10,075 by 0.60, obtaining $6,045.

Your share of the commission is 65% of that, so we multiply $6,045 by 0.65:

0.65($6,045) = $3,929.25.

Your personal share of the commission is thus $3,929.25.

4 0
3 years ago
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
The parent function f(x)=log^3x has been transformed by reflecting it over the X axis, stretching it vertically by a factor of t
NARA [144]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=x-%5Csqrt%7Bx%7D%20-2" id="TexFormula1" title="x-\sqrt{x} -2" alt="x-\sqrt{x} -2" align="absmi
Nata [24]

Answer:

(sqrt(x) +1)(sqrt(x)-2)

Step-by-step explanation:

x - 2 \sqrt{x}  +  \sqrt{x}  - 2 \\  \sqrt{x} ( \sqrt{x}  - 2) + 1( \sqrt{x}  - 2 ) \\ ( \sqrt{x}  + 1)( \sqrt{x}  - 2)

4 0
2 years ago
Two lines, A and B, are represented by equations given below: Line A: y = x − 4 Line B: y = 3x + 4 Which of the following shows
Ede4ka [16]
(-4,-8) because it satisfies both equations
5 0
3 years ago
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