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aleksandr82 [10.1K]
3 years ago
10

How to solve this equation correctly

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0
X equals 12 because  12 minus 2 equals 10 over 8 which you can simplify into 1 and 2 over 8  which can be simplified to 1 and 1 over 4 hope this helped
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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below.
Alecsey [184]
300*5=1500
150*5=750
75*5=375

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7 0
3 years ago
Will make brainliest answer!!
ch4aika [34]

Answer:

  • C. 5x - 1

Step-by-step explanation:

<h3>Given</h3>
  • f(x) = 3x-2 and g(x) = 2x+1
<h3>To find </h3>
  • (f+g)(x)
<h3>Solution</h3>
  • (f+g)(x) =
  • f(x) + g(x) =
  • 3x - 2 + 2x + 1 =
  • 5x - 1
3 0
3 years ago
What is the value of the expression?
const2013 [10]

Answer:

41

Step-by-step explanation:

Use the correct order of operations and do one step at a time to avoid making mistakes.

16 \div 4 + 2^3 \times 5 - 3 =

= 4 + 8 \times 5 - 3

= 4 + 40 - 3

= 44 - 3

= 41

6 0
3 years ago
Read 2 more answers
Define an operation ‘&amp;’ on the set of positive integers such that: 2 &amp; 1 = 5 3 &amp; 2 = 13 5 &amp; 3 = 34
Scilla [17]

Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes

7 0
4 years ago
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?
kondaur [170]

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, x_1=-8, y_1=-6, x_2=-4, y_2=-14

$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)

$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)

$P(x, y) =(-6, -10)

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Here, x_1=-6, y_1=-10, x_2=-8, y_2=-6

r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}

r=\sqrt{(-2)^{2}+(4)^{2}}

r=\sqrt{20} units

The standard form of the equation of a circle is

(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

(x+6)^{2}+(y+10)^{2}=20

Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

4 0
3 years ago
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