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Sauron [17]
3 years ago
15

Factor completely 16x^2+40x+25

Mathematics
2 answers:
Alex17521 [72]3 years ago
4 0

Answer:

Hence, the factor of given algebraic equation:

16x^2+40x+25 is:

(4x+5)^2=(4x+5)(4x+5)

Step-by-step explanation:

<em>" To factor an algebraic equation means to represent it in the most simplest form "</em>

Here we are given an algebraic equation as:

16x^2+40x+25

Now this algebraic equation could also be represented as:

16x^2+40x+25=(4x)^2+2\times (4x)\times 5+5^2\\\\16x^2+40x+25=(4x+5)^2

Hence, the factor of the given algebraic equation:

16x^2+40x+25 is:

(4x+5)^2=(4x+5)(4x+5)

Trava [24]3 years ago
3 0

Answer:

(4x+5)(4x+5)

Step-by-step explanation:

We have given an expression.

16x²+40x+25

We have to find the factor of given expression.

We use following formula to solve this:

a²+2ab+b² = (a+b)²

In given expression, a² = 4x² and b² = 25

Applying formula, we have

(4x)²+2(4x)(5)+(5)²

(4x+5)²

(4x+5)(4x+5)

Hence, the factors of give expression are (4x+5) and (4x+5).

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taurus [48]

Answer:

{ \tt{area = (7 \times 10) + (12 \times 4) + (5 \times 5)}} \\ { \tt{ = 70 + 48 + 25}} \\ { \tt{ = 143 \:  {in}^{2} }}

6 0
3 years ago
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Volumes of the solids with disk or shell method?
lina2011 [118]

The answer to the questions of volumes are given as follows

a) v=128 \pi

b) v=\frac{128}{3} \pi

 c)v=\frac{1024}{5} \pi

d)V=\frac{13568}{15} \pi

Generally, the questions are  mathematically solved below

y=\sqrt{x}, y=4, x=0

a) x-axis

if $y=4, x=16, x=0$

Using disk method

} v=\pi \int_{0}^{16}(\sqrt{x})^{2} d x \\

v=\pi\left(\frac{x^{2}}{2}\right)_{0}^{16} \\

v=\frac{\pi}{2} \times 16 \times 16 \\

v=128 \pi

b)  line y=4

if x=0, y=0 ;

y=\sqrt{x} \Rightarrow x=y^{2}

Using shell method

v = \int_{0}^{4} 2 \pi(4-y) \cdot y^{2} d y \\

v=2 \pi \int_{0}^{4}\left(4 y^{2}-y^{3}\right) d y

v=2 \pi\left[\frac{4 y^{3}}{3}-\frac{y^{4}}{4}\right]_{0}^{4} \\

v=\frac{2 \pi}{12}[1024-768] \\

v=\frac{512 \pi}{12} \\

v=\frac{128}{3} \pi

c) y-axis

0 ≤ y ≤ 4

x=y^2

Using disk method

volume

v=\pi \int_{0}^{4} y^{4} d y$

v=\pi\left(\frac{y 5}{5}\right)_{0}^{4}  \\

v=\frac{1024}{5} \pi

d) line x=-1

y=√x, y=4, x=0

0 ≤ x ≤ 6

Using shell method

volume is

V=\int_{0}^{16} 2 \pi(1+x) \sqrt{x} d x$

V=2 \pi\int_{0}^{16}(x^{1 / 2}+x^{3 / 2}\right) )d x\right. \\

V=2 \pi\left[\frac{x^{3 / 2}}{3 / 2}+\frac{x^{5 / 2}}{5 / 2}\right]_{0}^{16} \\

V=2 \pi\left[2 / 3 \cdot\left(4^{2}\right)^{3 / 2}+2 / 5\left(4^{2}\right)^{5 / 2}\right] \\

V=4 \pi / 3 \cdot 4^{3}+4 \pi / 5 \cdot 4^{5} \\

V=4 \pi\left(\frac{1}{3}+\frac{4^{2}}{5}\right)

V=\frac{256}{15}(5+48) \pi \\

V=\frac{256 \times 53}{15} \pi \\

V=\frac{13568}{15} \pi

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2 years ago
Help Please ill give branliest.
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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