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Sauron [17]
3 years ago
15

Factor completely 16x^2+40x+25

Mathematics
2 answers:
Alex17521 [72]3 years ago
4 0

Answer:

Hence, the factor of given algebraic equation:

16x^2+40x+25 is:

(4x+5)^2=(4x+5)(4x+5)

Step-by-step explanation:

<em>" To factor an algebraic equation means to represent it in the most simplest form "</em>

Here we are given an algebraic equation as:

16x^2+40x+25

Now this algebraic equation could also be represented as:

16x^2+40x+25=(4x)^2+2\times (4x)\times 5+5^2\\\\16x^2+40x+25=(4x+5)^2

Hence, the factor of the given algebraic equation:

16x^2+40x+25 is:

(4x+5)^2=(4x+5)(4x+5)

Trava [24]3 years ago
3 0

Answer:

(4x+5)(4x+5)

Step-by-step explanation:

We have given an expression.

16x²+40x+25

We have to find the factor of given expression.

We use following formula to solve this:

a²+2ab+b² = (a+b)²

In given expression, a² = 4x² and b² = 25

Applying formula, we have

(4x)²+2(4x)(5)+(5)²

(4x+5)²

(4x+5)(4x+5)

Hence, the factors of give expression are (4x+5) and (4x+5).

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